Do this maths. It R Hard.
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@Yamikuronue If there was 48% non-whites in the UK, the UK would be a very different country. :D
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@lucas1 We call that America, son, it's a freedom thing ;)
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@asdf What is an "atan" again?
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@lucas1 I think arctangent?
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@lucas1 The inverse of the tangent function.
tan α = opposite side / adjacent side = 10/20 = 0.5
=> α = atan(0.5)
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@asdf yeah 1 / tan or "inv tan" on my old scientific calculator.
Corrected this is it. Man I loved this calculator. It worked backwards not like this DAL nonsense for fucking twats.
EDIT: We never called it arc-tan. It was the inverse of tan basically.
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@Yamikuronue We have this freedom thing in the UK too.
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@lucas1 said in Do this maths. It R Hard.:
We have this freedom thing in the UK too.
Is that why London looks like 1984?
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@lucas1 You win, I can't keep up the fake-Texas attitude much longer XD
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@asdf London !== UK
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@lucas1 Ah, OK, so same as Berlin != Germany and Munich != Bavaria. Got it.
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@Yamikuronue I love the US as much as sometimes I say "FFS americans being americans again". It basically all the eccentrics from our country got turned upto 11.
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@asdf Kind of. There is a big North / South divide in England in terms of wealth and culture. There is a massive difference in culture between different areas of London and in London vs the rest of the UK. Then there are massive differences in culture between Scotland, Northern Island and Wales and England.
London is 75 miles in a straight line from where I live but they are worlds apart.
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@lucas1 Same in Germany. There is a cultural north/south divide (the south is also slightly wealthier) and a huge east/west divide for obvious reasons. There are very rural areas in the northeast, in Bavaria and west of the Rhine. Also, there are some special
cities like Berlin and Munich, whose inhabitants tend to think that the rest of Germany doesn't matter.
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@asdf Sounds pretty similar to be honest.
I was listening to a podcast and they said that Bavaria are just revolting pretty much against Berlin? Is this true?
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@lucas1 said in Do this maths. It R Hard.:
I was listening to a podcast and they said that Bavaria are just revolting pretty much against Berlin? Is this true?
Pretty much. Bavaria has always been different, and very conservative (apart from Munich, which is a special
, as mentioned above). They even have their own conservative party (CSU), which has always worked together with Merkel's party (CDU), but has its own agenda. It is also pretty corrupt, sometimes borderline nationalist and the origin of 70% of the outrageously stupid ideas in our national parliament.Right now, the CSU is criticizing Merkel in an effort not to lose their right-wing voters to the AfD. A few months ago I thought their union might finally break, which would be a reason to celebrate, because it will most certainly mean that the CSU will lose their >50% majority in Bavaria.
Let's just say that the CSU is the reason why I don't live in Bavaria anymore…
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@asdf said in Do this maths. It R Hard.:
Munich
For some reason, I mentally have trouble linking up the English name Munich with the Dutch/German equivalent (München). Though not as badly as Cologne (Keulen/Köln).
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The area of a circle is pi*r^2. The circumference of a circle is 2*pi*r.
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@Maciejasjmj said in Do this maths. It R Hard.:
Calculate the black area.
First of all, decompose the rectangle into two 10x10 squares. The area of one square is 102 = 100, the area of the circle inside it is π52 = 25π. The subtraction of the circle from the square is 100 - 25π, and it is made up of four identical shapes in the 4 corners of the square, each shape having an area of 25 - 6.25π. The left square has 1 corner shaded and the right square has 2 plus a part of the third. Of the three entirely shaded corners, the area is 75 - 18.75π. This leaves the last part of a corner, which is the area of a 5x10 right triangle, which is 25, less the area of the portion of the circle inside it. The area of the portion of the circle inside the triangle can be decomposed into an isosceles triangle and a circular sector:
As α is the corner of a 5x10 right triangle, its angle is tan-15/10 = tan-10.5. Due to symmetry, α is also the other angle of the triangle inside the circular sector, as labeled. The central angle of the sector, θ = π - 2α = π - 2tan-10.5. The area of that triangle is (52/2) sin θ = 12.5 sin(π - 2tan-10.5). The angle of the circular sector is the supplement of θ, θ' = π - θ, and its area is (52/2) θ' = 12.5(π - θ) = 12.5(2tan-10.5) = 25 tan-10.5.
So the shaded area in the above diagram is 25 - 12.5 sin(π - 2 tan-10.5) - 25 tan-10.5, and when added to the rest of the shaded areas from the original diagram:
75 - 18.75π + 25 - 12.5 sin(π - 2 tan-10.5) - 25 tan-10.5
100 - 18.75π - 12.5 sin(π - 2 tan-10.5) - 25 tan-10.5
~= 19.5
As a sanity check, this should be slightly less than half the entire area between the circles and the rectangle, which can easily be calculated as 2(102 - π 52) ~= 42.92. Half of that is about 21.46, and each shaded corner is about 5.37. As I said before that between 3 and 4 of the corners were shaded, the area falls between about 16.1 and about 21.5, and the extra shaded fraction of a corner in the upper left is definitely the larger portion of that corner so you'd expect it to be closer to 21.5 than to 16.1. The result I found above, about 19.5, falls between these and is closer to 21.5, so it falls within the expected range for the result.
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@Maciejasjmj said in Do this maths. It R Hard.:
Calculate the black area.
Oh common ... at least you could have drawn some nipples too ...
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@anotherusername You posted the explanation I was too lazy to draw last night.
