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RE: The Official Status Thread
For those better at math than me (which is everyone), if you have x^(y*z) and you know x and z, you can compute x^y by taking the z'th root, right? You just obviously can't feasibly compute y; that'd be a discrete logarithm.
Yes. x^(y*z) is the same as (x^y)^z, so you can take the root